Question

please solve this question

Answer 1

Hiii. .....friend

The answer is here,

Given that,

$= > \: \frac{x}{y} + \frac{y}{x} = - 1$

$= > \: \frac{ {x}^{2} + {y}^{2} }{xy} = - 1$
$= > \: {x}^{2} + {y}^{2} = - xy$

$= > \: {x}^{2} + {y}^{2} + xy = 0$

We have to find the value of,

$= > \: {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + {y}^{2} + xy)$

$= > \: {x}^{3} - {y}^{3} = (x - y)(0)$

$= > \: {x}^{3} - {y}^{3} = 0$

:-)Hope it helps u.