Question

please solve this question​

Answer 1

Step-by-step explanation:

$\frac{1 + {tan}^{2}A }{1 + {cot}^{2}A }$

$\frac{ {sec}^{2} A}{ {cosec}^{2}A }$

$\frac{1}{ {cos}^{2}A } \times \frac{ {sin}^{2}A }{1}$

${tan}^{2} A$

Answer 2

Step-by-step explanation:

:

\frac{1 + {tan}^{2}A }{1 + {cot}^{2}A }1+cot2A1+tan2A

\frac{ {sec}^{2} A}{ {cosec}^{2}A }cosec2Asec2A

\frac{1}{ {cos}^{2}A } \times \frac{ {sin}^{2}A }{1}cos2A1×1sin2A

{tan}^{2} Atan2A