Question

please solve this question

Answer 1

Here is your answer.........!!☺⤵❗❗


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, Most important : Ball is thrown in upward direction.

#Step and Understanding :

1) Let the initial velocity of first ball be "u " m/s

And,
The one possibility for the gap to remain constant is that :
Both balls has same velocity after second ball is thrown.

2) Implies speed of first ball when second ball is thrown is (u) /2


First ball :
Distance covered, S = 15m
Initial velocity , u = u m/s (say)
Final velocity , v = u/2 m/s

By Newtons third equation of motion,
$v ^{2} = u^{2} + 2( - g)s$
=) (u/2)^2 = u^2 - 2gs
=) 3/4 u^2 = 2gs
=) u^2= 4/3 × 2× 10 × 15
=) u^2 = 400
=) u = 20m ÷ s

3) Therefore, Velocity of first ball: 20m /s in upward direction.
Velocity of second ball is 10m/s in upward direction.

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