please solve this question
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take numerator and denominator as x and y
ATQ
x/y=x-3/y
3x/y+20=1/8
solve for x and y and then write them as x/y you'll get the answer
ATQ
x/y=x-3/y
3x/y+20=1/8
solve for x and y and then write them as x/y you'll get the answer
ohhjj:
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Answered by
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Q 12
Our equation will be n-3 / n.
Then.. 3(n-3) / n+20 = 1/8
3n-9 / n+20 = 1/8
Cross multiply..
8(3n-9) = 1(n+20)
24n-72 = n+20
23n = 92
n = 4
Therefore, your original number is 1/4.
Please mark brainliest or thanks if it helped! :D
It would mean a lot!!
Our equation will be n-3 / n.
Then.. 3(n-3) / n+20 = 1/8
3n-9 / n+20 = 1/8
Cross multiply..
8(3n-9) = 1(n+20)
24n-72 = n+20
23n = 92
n = 4
Therefore, your original number is 1/4.
Please mark brainliest or thanks if it helped! :D
It would mean a lot!!
thank you very much <3
you're welcome
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