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Step-by-step explanation:
Let us consider,
Speed of the train = x km/h
Speed of the bus = y km/h
According to the given question,
60/x + 240/y = 4 …………………(1)
100/x + 200/y = 25/6 …………….(2)
Put 1/x=m and 1/y=n, in the above two equations;
60m + 240n = 4……………………..(3)
100m + 200n = 25/6
600m + 1200n = 25 ………………….(4)
Multiply eq.3 by 10, to get,
600m + 2400n = 40 ……………………(5)
Now, subtract eq.4 from 5, to get,
1200n = 15
n = 15/1200 = 1/80
Substitute the value of n in eq. 3, to get,
60m + 3 = 4
m = 1/60
m = 1/x = 1/60
x = 60
And y = 1/n
y = 80
Therefore,
Speed of the train = 60 km/h
Speed of the bus = 80 km/h
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