Math, asked by tanwarbuhana, 8 hours ago

Please solve this question ​

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Answers

Answered by chandrasekharjnv9365
0

Answer:

(√3-1)×2={2√3-2) is the answer

Answered by parmar11chanda1987
0

Answer:

Rationalize the denominator of \frac{2}{\sqrt{3}-1}

3

−1

2

by multiplying numerator and denominator by \sqrt{3}+1

3

+1.

2\sqrt{3}-\frac{2\left(\sqrt{3}+1\right)}{\left(\sqrt{3}-1\right)\left(\sqrt{3}+1\right)}2

3

(

3

−1)(

3

+1)

2(

3

+1)

Step 2

Consider \left(\sqrt{3}-1\right)\left(\sqrt{3}+1\right)(

3

−1)(

3

+1). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}(a−b)(a+b)=a

2

−b

2

.

2\sqrt{3}-\frac{2\left(\sqrt{3}+1\right)}{\left(\sqrt{3}\right)^{2}-1^{2}}2

3

(

3

)

2

−1

2

2(

3

+1)

Step 3

Square \sqrt{3}

3

. Square 11.

2\sqrt{3}-\frac{2\left(\sqrt{3}+1\right)}{3-1}2

3

3−1

2(

3

+1)

Step 4

Subtract 11 from 33 to get 22.

2\sqrt{3}-\frac{2\left(\sqrt{3}+1\right)}{2}2

3

2

2(

3

+1)

Step 5

Cancel out 22 and 22.

2\sqrt{3}-\left(\sqrt{3}+1\right)2

3

−(

3

+1)

Step 6

To find the opposite of \sqrt{3}+1

3

+1, find the opposite of each term.

2\sqrt{3}-\sqrt{3}-12

3

3

−1

Step 7

Combine 2\sqrt{3}2

3

and -\sqrt{3}−

3

to get \sqrt{3}

3

.

\sqrt{3}-1

3

−1

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