Question

please solve this question.​

Answer 1

[Procedure attached. :)]

First of all we assumed Y to be 1/y & X to be 1/x. Further we wrote the both eqns in form of X and Y and solved them. Later we found x to be 6 and y to be - 4.

Answer 2

Solution:

Given Equations:

$\rm \longrightarrow \dfrac{2}{x} + \dfrac{2}{3y} = \dfrac{1}{6} - (i)$

$\rm \longrightarrow \dfrac{3}{x} + \dfrac{2}{y} = 0 - (ii)$

Multiplying equation (i) by 3, we get:

$\rm \longrightarrow \dfrac{6}{x} + \dfrac{2}{y} = \dfrac{1}{2} - (iii)$

Subtracting (ii) from (iii), we get:

$\rm \longrightarrow \dfrac{6}{x} - \dfrac{3}{x} = \dfrac{1}{2}$

$\rm \longrightarrow \dfrac{3}{x} = \dfrac{1}{2}$

$\rm \longrightarrow \dfrac{x}{3} = 2$

$\rm \longrightarrow x = 6$

Substituting the value of x in (i), we get:

$\rm \longrightarrow \dfrac{2}{6} + \dfrac{2}{3y} = \dfrac{1}{6}$

$\rm \longrightarrow \dfrac{2}{3y} = \dfrac{1}{6} - \dfrac{2}{6}$

$\rm \longrightarrow \dfrac{2}{3y} = \dfrac{ - 1}{6}$

$\rm \longrightarrow \dfrac{2}{y} = \dfrac{ - 1}{2}$

$\rm \longrightarrow \dfrac{y}{2} = - 2$

$\rm \longrightarrow y = - 4$

Therefore:

$\rm \longrightarrow (x, y) = (6,-4)$

★ Which is our required answer.

Answer:

• The values of x and y are 6 and -4 respectively.