please solve this question
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x + 1/x = 5
squaring. both sides we get,
x² + 1/x² + 2 × x × 1/x = 25
=> x² + 1/x² + 2 = 25
=> x² + 1/x² = 23______________1
now square x - 1/x
=> (x - 1/x)² = x² + 1/x² - 2 × x × 1/x
=> (x - 1/x)² = x² + 1/x² - 2
=> (x - 1/x)² = 23 - 2 [ from 1 (x² + 1/x²) = 23
=> (x - 1/x)² = 21
taking square root on both sides,
=> x - 1/x = √21 Answer
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