please solve this question
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Let the lever of water in the pona nses py 21 cm in t hours.
Speed of water = 15 km/hr
Diameter of the pipe = 14/100 m
Radius of the pipe (r) = 7/100 m Volume of water flowing out of the pipe in 1 hour
= πr²h
= (22/7) x (7/100) x (7/100) x 15000
= 231 m³
Volume of water flowing out of the pipe in t hours = 231 tm³.
Volume of water in the cuboidal pond
= 50 x 44 x (21/100)
= 462 m³
Volume of water flowing out of the pipe in t hours =
Volume of water in the cuboidal pond
So, 231 t = 462
t = 2
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Answer:
the required time will be 2 hours
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