please solve this question 50 points
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Step-by-step explanation:
when two chor intersect each other 4 angles are formed
by the theorem intersection of two chord
∠1 + ∠3 =78
∠2 =half of ∠1 + ∠3 =78
∠2= 19 degree
these example is solve by theorem of intersection of two chord of 10 standard.
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angle 1 +angle 3=78
angle 1= angle 3(vertically opposite angles)
angle 1+angle 1=78
2(angle 1) = 78
angle 1= 78/2
angle 1=39=angle 3
angle 3 + angle 2= 180(linear pair)
39+angle2 =180
angle 2 = 180-39
angle 2 = 141
hope it helps!
angle 1= angle 3(vertically opposite angles)
angle 1+angle 1=78
2(angle 1) = 78
angle 1= 78/2
angle 1=39=angle 3
angle 3 + angle 2= 180(linear pair)
39+angle2 =180
angle 2 = 180-39
angle 2 = 141
hope it helps!
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