please solve this question 55
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here is ur answer buddy...
LHS,
(1-sin²A)/1+sin²A=cos²A/1+sin²A
RHS,
=>1/(Sec²A+tan²A)=1/{(1/cos²)+(sin²A/cos²A)}
=>1/{1+sin²A)/cos²
=>cos²/1-sin²A
LHS=RHS
HENCE PROVED
HOPE IT HELPS
IF POSSIBLE MARK ME AS BRAINLIEST
LHS,
(1-sin²A)/1+sin²A=cos²A/1+sin²A
RHS,
=>1/(Sec²A+tan²A)=1/{(1/cos²)+(sin²A/cos²A)}
=>1/{1+sin²A)/cos²
=>cos²/1-sin²A
LHS=RHS
HENCE PROVED
HOPE IT HELPS
IF POSSIBLE MARK ME AS BRAINLIEST
jude0704:
cosA/sinA=2/1
cosA/(1+sinA)=2sinA/1+sinA
2sinA+2
sorry
the correct one is
sinA/1+cosA
cross multiplication
cosA(1+cosA)+sin²A/(sinA(1+cosA))
(cosA+cos²A+sin²A)/sinA(1+cosA)
the answer is √5/3
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