Question

please solve this question

Answer 1

hope this helps you.....

Answer 2

Given,

$\frac{1}{x-3}+\frac{2}{x-2}=\frac{8}{x}\\\;\\\frac{x-2+2x-6}{(x-2)(x-3)}=\frac{8}{x}\\\;\\\frac{3x-8}{x^{2}-5x+6}=\frac{8}{x}\\\;\\3x^{2}-8x=8x^{2}-40x+48\\\;\\5x^{2}-32x+48=0\\\;\\5x^{2}-20x-12x+48=0\\\;\\5x(x-4)-12(x-4)=0\\\;\\(5x-12)(x-4)=0\\\;\\x=4\;\;\;or\;\;\;x=\frac{12}{5}$