Question

please solve this question

Answer 1

17.in the diagram  AE is the bisector of angle CAB So, ANGLE CAE=Angle EAB EBis the bisector of ANGLE CBD So, ANGLE EBD=ANGLE EBC SO ANGLE CAB=2EAB ANGLE CBD=2EBD IN TRIANGLE CAB  CBD =CAB+BCA BCA=CBD-CAB =2EBD-2EAB =2(EBD-EAB) LET IT BE EQUATION ONE IN TRIANGLE EAB EBD=AEB +EAB AEB=EBD-EAB LET IT BE EQUATION TWO  PUT TWO IN ONE BCA=2(AEB) 2(AEB)=BCA AEB=1/2BCA HENCE PROVED   PLS MARK AS BRAINLIEST