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Given,area of an equilateral triangle
= 484√3cm^2
let a be the side of equilateral triangle .
according to question ,
Area = 484 √3 cm^2
√3 /4 (a )^2 = 484 √3
a^2 = 4 × 484 × √3 /√3
a^2 = 1936
a = 44 cm
length of wire = perimeter of equilateral triangle = 3 × side
= 3 × 44 = 132 cm
since, the length of wire is same , then
perimeter of equilateral triangle
will be = circumference of circle
132 cm = 2 π r
r = 132× 7 / 22 × 2 = 21 cm
radius of circle = 21 cm
then , area of circle = π r^2
= 22 / 7 ( 21 )^2 = 1386 cm^2
therefore ,
area of circle = 1386 cm^2 _______________________________
Your Answer : 1386 cm^2
_______________________________
= 484√3cm^2
let a be the side of equilateral triangle .
according to question ,
Area = 484 √3 cm^2
√3 /4 (a )^2 = 484 √3
a^2 = 4 × 484 × √3 /√3
a^2 = 1936
a = 44 cm
length of wire = perimeter of equilateral triangle = 3 × side
= 3 × 44 = 132 cm
since, the length of wire is same , then
perimeter of equilateral triangle
will be = circumference of circle
132 cm = 2 π r
r = 132× 7 / 22 × 2 = 21 cm
radius of circle = 21 cm
then , area of circle = π r^2
= 22 / 7 ( 21 )^2 = 1386 cm^2
therefore ,
area of circle = 1386 cm^2 _______________________________
Your Answer : 1386 cm^2
_______________________________
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