Math, asked by shivani1l, 1 year ago

please solve this question

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Answered by Anonymous
4

y^2-5y+6=0

(y^2-2y)-3y+6=0

y(y-2)-3(y-2)=0

(y-2)(y-3)=0

y-2=0 and y-3=0

y=2 and 3 is the answer.


Hope it is helpful to you!!:):)



Answered by shisan8
1
this is the ans of ur question
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