please solve this question
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i ) sin2A=1
sin2A=sin90° (sin90°=1)
2A=90°
A=90°/2
A=45°
ii) 2sin2A=1
sin2A=1/2
sin2A=sin30°
2A=30°
A=30°/2
A=15°
2sinA=1
sinA=1/2
sinA=sin30°
A=30°
I hope this helps.
sin2A=sin90° (sin90°=1)
2A=90°
A=90°/2
A=45°
ii) 2sin2A=1
sin2A=1/2
sin2A=sin30°
2A=30°
A=30°/2
A=15°
2sinA=1
sinA=1/2
sinA=sin30°
A=30°
I hope this helps.
kavya8947:
thank u soo much
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