please solve this question
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its forms 180
the next 50+50+80 = 180
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90degree angle of EFC
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Angle AFD = angle BFC = 50
Also, angle EFA = angle AFD = 50
Angle ( EFA + EFC + BFC ) = 180 [linear pair]
=> 50 + angle EFC + 50 = 180
=> angle EFC = 180 - 100
=> angle EFC = 80 .
Also, angle EFA = angle AFD = 50
Angle ( EFA + EFC + BFC ) = 180 [linear pair]
=> 50 + angle EFC + 50 = 180
=> angle EFC = 180 - 100
=> angle EFC = 80 .
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