Question

please solve this question

Answer 1

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( √2 )^x = 2^8

( 2^1/2 )^x = 2^8

( 2 )^( x / 2 ) = 2^8

since , the base are equal then it will get cancel to each other.

so now we have ,

x / 2 = 8

x = 2 × 8

x = 16
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Answer : x = 16
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extra :
● a^m × a^n = a^(m + n )

● a^m / a^n = a^( m - n )

● if a^n = b

then ,

a = b^(1/ n ) or n√b

● if a^(1 / n ) = b

then,

a = b^n
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Answer 2

(Root2) ^x = 2 ^8

Root 2)^x = (root2)^ 2 ☓ 8

(root 2) ^x = (root 2) ^16

x = 16

[since a^x = a^b then x = b]