Question

please solve this question.

Answer 1

∠ EPA = ∠ DPB (Given)

⇒ ∠ EPA + ∠DPE = ∠ DPB + ∠DPE

∴ ∠APD = ∠BPE

Consider Δ’s DAP and EBP

AP = BP (Given P is midpoint of AB)

∠BAD = ∠ABE (Given)

∠APD = ∠BPE (Proved)

Hence ΔDAP ≅ ΔEBP (By ASA congruence rule)

⇒ AD = BE (CPCT)

Answer 2

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