please solve this QUESTION
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hope you understand and follow me
another question you asked in the comment hope you understand
u= tanx
du/dx = sec2x
= ∫ tan4x dx
= ∫ tan2x tan2x dx
= ∫ tan2x (sec2x - 1) dx
= ∫ tan2x sec2x dx - ∫ tan2x dx
= ∫ u2 du - ∫ (sec2x - 1) dx
= (1/3)u3 - (tanx - x) + C
= (1/3)tan3x - tanx + x + C
another question you asked in the comment hope you understand
u= tanx
du/dx = sec2x
= ∫ tan4x dx
= ∫ tan2x tan2x dx
= ∫ tan2x (sec2x - 1) dx
= ∫ tan2x sec2x dx - ∫ tan2x dx
= ∫ u2 du - ∫ (sec2x - 1) dx
= (1/3)u3 - (tanx - x) + C
= (1/3)tan3x - tanx + x + C
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snehachikki:
solve it
f?
what is f
integrate??
Integrate it
yes
ok
i done the ans but how i send you the answer
??
can you write the question again but not on comment ok
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