Please solve this question
Attachments:
Answers
Answered by
1
Thickness = 0.01 m = 1 cm
Outer radius = inner radius + 2 × thickness
Inner radius = 12/2 = 6 cm
=> Outer radius = 6 + 2 × 1
= 6 + 2
= 8 cm
=> Outer surface area = 4πr²
=> 4 × 22/7 × 8²
=> 5632/7 cm²
Answer ;- 5632/7 cm²
Volume of sphere = 4/3× πr³
=> Volume of sphere = 4/3 × 22/7 × 8³
= 45056/21
Mass = Density × Volume
=> mass = 8.88 × 45056/21
=> mass = 400097.28/21
=> mass = 19052.25 gram (approx)
=> mass = 19.05 kg (approx)
Outer radius = inner radius + 2 × thickness
Inner radius = 12/2 = 6 cm
=> Outer radius = 6 + 2 × 1
= 6 + 2
= 8 cm
=> Outer surface area = 4πr²
=> 4 × 22/7 × 8²
=> 5632/7 cm²
Answer ;- 5632/7 cm²
Volume of sphere = 4/3× πr³
=> Volume of sphere = 4/3 × 22/7 × 8³
= 45056/21
Mass = Density × Volume
=> mass = 8.88 × 45056/21
=> mass = 400097.28/21
=> mass = 19052.25 gram (approx)
=> mass = 19.05 kg (approx)
Answered by
5
Here is your answer- my friend..
Hope it helps you..!✌️✌️
Hope it helps you..!✌️✌️
Attachments:
Similar questions