Question

please solve this question

Answer 1

ANSWER:

let p(x)=2x^4+3x^3+2kx^2+3x+6

p(-2)=0  (given)

p(-2)=2(-2)^4+3(-2)^3+2k(-2)^2+3*-2+6

0=2*16+3*-8+2k*4-6+6

0=32-24+8k+6-6

0=8+8k

8k=-8

k=-1