Math, asked by DipGoswami, 1 year ago

Please solve this question ​

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afsanafatima5: yes equal h dono

Answers

Answered by errorusername123
1

Answer:

\frac{a^{-1}}{a^{-1}+b^{-1}}+\frac{a^{-1}}{a^{-1}-b^{-1}}=\frac{\frac{1}{a}}{\frac{1}{a}+\frac{1}{b}}+\frac{\frac{1}{a}}{\frac{1}{a}-\frac{1}{b}}=\frac{b}{b+a}+\frac{b}{b-a}=b\left[\frac{b-a+b+a}{b^{2}-a^{2}}\right]=\frac{2b^2}{b^2-a^2}

Answered by wwwalison8888a
4

LHS

2{(1/a)/(1/a+1/b)}......as both terms on LHS are equal

2{(1/a)/(b+a/ab)}

2*1/a*(ab/b+a)

2b/b+a= RHS...


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