please solve this question...
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Let two squares be X and Y
ATQ..
difference between their perimeter is..
4x - 4y = 24
x-y =6 .....(1)
x= y+6..(2)
x²+y²=468
(y+6)²+y² = 468
y²+36 + 12y + y²=468
2y²+12y - 432 =0
y²+ 6y - 216=0
y²+(18-12)y - 216 =0
y² + 18 y - 12y - 216 =0
y(y+18) -12(y +18)=0
(y-12)(y+18)
y=12cm
x= 18cm
HOPe iT hElpS!!!!
ATQ..
difference between their perimeter is..
4x - 4y = 24
x-y =6 .....(1)
x= y+6..(2)
x²+y²=468
(y+6)²+y² = 468
y²+36 + 12y + y²=468
2y²+12y - 432 =0
y²+ 6y - 216=0
y²+(18-12)y - 216 =0
y² + 18 y - 12y - 216 =0
y(y+18) -12(y +18)=0
(y-12)(y+18)
y=12cm
x= 18cm
HOPe iT hElpS!!!!
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