Question

please solve this question​

Answer 1

Answer:

Step-by-step explanation:

In ∆dxy and∆dab

Angle xdy= angle adb (common)

Angle xyd= angle abd=90°

∆dxy ~ ∆dab (by AA)

Therefore, c/a=dy/db (i)

Similarly, ∆bxy~∆bcd (by AA)

Therefore, c/b = by/bd (ii)

On adding (i) and (ii)

c/a +c/b= by/bd+dy/bd

c(1/a+1/b)= by+dy/bd

c(a+b/ab)=bd/bd

c(a+b/ab)= 1

c(a+b)= ab

Hence proved