Question

please solve this question​

Answer 1

hence proved. i hope it helps

Answer 2

Answer:

Step-by-step explanation:

Let CD perpendicular to AB

Then CD=p

Area of triangle ABC=1/2*(AB*CD)

=1/2cp

ALSO,Area of triangle ABC=1/2*(BC*AC)=1/2ab

1/2cp=1/2ab

cp=ab (proved)

NOW,Since ABC is a triangle right angled at C

AB^2=BC^2+AC^2

=c^2=a^2+b^2

=(ab/p)^2=a^2+b^2

=(a^2b^2)/p^2=a^2+b^2

=1/p^2=(a^2+b^2)/a^2b^2

THEN,1/p^2=1/b^2+1/a^2

   =1/p^2=1/a^2+1/b^2