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Answer:
Step-by-step explanation:
Area of segment = @/360 × πr^2
= 120/360 × 22/7 ×21×21
= 462 sq cm
We know area of segment = (l×r)/2
l×r/2 = 462
l× 21/2 =462
l=44 cm
ABY is semicircle .
πr =44
r= 14cm
Area of semicircle AYB
πr^2
= 22/7 × 14×14
= 44×14
=616sq cm
Answer -616sq cm
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