Question

please solve this question​

Answer 1

hope it helps you..............

Answer 2

Answer:

1

Step-by-step explanation:

$Given:f(x) = \frac{sin^2x + cos^4x}{cos^2x + sin^4x}$

$=\frac{sin^2x + (1 - sin^2x)^2}{cos^2x + sin^4x}$

$=\frac{sin^2x + 1+sin^4x - 2sin^2x}{cos^2x + sin^4x}$

$=\frac{1 + sin^4x - sin^2x}{cos^2x + sin^4x}$

$=\frac{cos^2x + sin^4x}{cos^2x + sin^4x}$

$=1$

Therefore, f(2015) = 1.

Hope it helps!