please solve this question
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Answered by
0
( a + b )³ - ( a - b )³ = 2b³ + 6a²b or 2b(3a² + b²)
and -6b(a+b)(a-b)
now we get
2b(b^2+3a^3)-6b(a^2-b^2)
now after solving get the answer ...
Answered by
1
(a+b)^3 -(a-b)^3 -6b(a^2 -b^2)
=a^3 +b^3 + 3(a+b)ab -(a^3-b^3-3ab(a-b)) -6b(a+b)(a-b)
=a^3+b^3+3ab(a+b) -a^3 +b^3 +3ab(a-b)-6b(a+b)(a-b)
=3ab(a+b) +b^3 +3ab(a-b)-6b(a-b)(a+b)
=3ab(a+b+a-b) +b^3 -6b(a-b)(a+b)
=6ab(a)+b^3 -6b(a-b)(a+b)
=6b(a^2-a^2+b^2)+b^3
=6b(b^2) +b^3
=7b^3
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