please solve this question
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Step-by-step explanation:
let x no: be cows and y no: be hens,
now, as hens have two legs and cows have 4,
so, 4x+2y= 128 and, x+y=40⇒y=40-x
substituting y in 1 equation,
4x + 2(40-x) = 128
4x + 80 -2x = 128
2x = 48⇒x=24
SUBSTITUTING X IN Y=40-X
⇒y=40-24 = y=16
∴THERE ARE 24 COWS AND 16 HENS
PLZ MARK AS BRAINLIEST
some other method with algebra only can you solve
THIS IS ONE ALGEBRAIC METHO
METHOD
SUBSTITUTION METHOD
ISN'T THIS ENOUGH????
no because till now I am not having this method I am in 6th standard
OH....THEN TAKE NUMBER OF COWS X THEN NO: OF CHICKEN WILL BE 40-X.........
NOW DO IT
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