Please solve this question 9...
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in triangle AML and triangle CMN
AM=CM (diagonals of parallelogram bisect each other)
angle AML = angle CMN ( opposite angles)
angle LAM = angle NCM ( alternate interior angles are equal)
therefore by ASA congruency triangle AML is congruent to triangle CMN
that implies LM =NM by CPCT
implies M is the mid point of LN.
hence proved
AM=CM (diagonals of parallelogram bisect each other)
angle AML = angle CMN ( opposite angles)
angle LAM = angle NCM ( alternate interior angles are equal)
therefore by ASA congruency triangle AML is congruent to triangle CMN
that implies LM =NM by CPCT
implies M is the mid point of LN.
hence proved
Pavitra15:
Ok thanku...
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