Question

please solve this question​

Answer 1

ar(shaded region) = ar(sector) - ar(triangle)

$\implies \: \dfrac{\pi {r}^{2} \theta}{360} - \dfrac{1}{2} bh \\ \\ \implies \: \dfrac{22 \times 8 \times 8 \times 120}{7 \times 360} - \dfrac{1}{2} \times 8 \times 8 \\ \\ \implies \: \dfrac{22 \times 64}{21} - 32 \\ \\ \implies \: 67.04 - 32 \\ \\ \implies \: 35.04 \: sq. \: units$