Math, asked by karthikashok, 1 year ago

please solve this question​

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Answered by adarsh08
1

Answer:

Step-by-step explanation:

the zeroes of the equation are 2 and 4

take, alpha=2 beta=4

i) 1\4 + 1\2

=3\4

ii) (2)^3 (4)^4 + (2)^4 (4)^3

 = (8 x 256) + ( 16 x 64 )

 = 2048 + 1024

 = 3072

iii) 2\4 +4\2

  = 1\2 + 2

   =5\2

Answered by priya1583766431
0

if we take the eqation as

ax ^{2}   + bx + c = 0

then a= 1

b= -6

c=8

the sum of zeroes is = -b/a

 \alpha  +  \beta  = 6

and the multiple of zeroes = c/a

 \alpha  \beta  = 8

(1)

(1 \div  \alpha) +( 1  \div   \beta) =( \alpha  +  \beta ) \div  \alpha  \beta

put the value of

= 6/8

= 3/4

I know only one part sorry


ravishankar1011: hiii
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