Question

please solve this question​

Answer 1

$\bold\red{Solution \: by \: RKRAUSHAN}$

${3}^{x - 1} = {3}^{2} \\ x - 1 = 2 \\ x = 3$

${4}^{y + 2} = {4}^{3}$

$y + 2 = 3 \\ y = 1$

$now...... \\ \\ \frac{ {y}^{2} \: - {x}^{2} }{xy}$

$=>\frac{1 - 9}{3} = \frac{ - 8}{3}$

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$\bold\red{Thank \: U}$