Question

please solve this question ​

Answer 1

As from A perpendicular drawn to BC bisects it

Therefore it is isosceles triangle

So AB= AC

A(6,6) B(-3,3) C(9,k)

AB^2 = AC^2

( 6+3)^2 + ( 6-3)^2 = ( 9-6)^2 + ( k-6)^2

9^2 + 3^2 = 3^2 + (k-6)^2

9^2 = (k-6)^2

k-6 = +-9

k= 9+6 = 15 , k= -9+6= -3