Question

please solve this question​

Answer 1

$\displaystyle\frac{3x+1}{x-1}+\frac{2x+3}{x+1}=5\\\\\\\frac{\big[(3x+1)(x+1)\big]+\big[(2x+3)(x-1)\big]}{(x-1)(x+1)}=5\\\\\\\\\frac{\big[3x^2+3x+x+1\big]+\big[2x^2-2x+3x-3\big]}{(x-1)(x+1)}=5\\\\\\\\\frac{\big[3x^2+4x+1\big]+\big[2x^2+x-3\big]}{(x^2-1^2)}=5\\\\\\\frac{5x^2+5x-2}{x^2-1}=5\\\\\\5x^2+5x-2=5x^2-5\\\\5x-2=-5\\\\5x=-3\\\\\\\underline{\underline{x=\frac{-3}{5}}}$

Answer 2

here's your answer my friend