Question

please solve this question along with detailed procedure( question 11)

Answer 1

body move from rest,so initial velocity(u)=0
S=270m
t=3s
By using the equation,
s=ut+ 1/2at^2
270= 0×3+1/2×a×(3)^2
270= 9a/2
270×2=9a
540=9a
a=60m/s^2

Now using the equation
v=u +at
v= 0+ 60× 10
v = 600m/s