Question

please solve this question and let me also please ​

Answer 1

Answer:

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Answer 2

$1.{ - 4}^{5 - 8} = { - 4}^{ - 3} = \frac{ - 1}{ { 4}^{3} }$

$2. {a}^{3 + 2 + ( - 5)} = {a}^{0} = 1$

$3.{2}^{2 \times - 3} = {2}^{ - 6} or \frac{1}{ {2}^{6} }$

$4.x + ( - 4) = 5 = > x - 4 = 5 = > x = 5 + 4 = > x = 9$

$5.( {3}^{ - 7 - ( - 9)} ) \times {3}^{ - 4} = > {3}^{2} \times {3}^{ - 4} = > {3}^{2 + ( - 4)} = > {3}^{ - 2} = > \frac{1}{ {3}^{2 } } = > \frac{1}{9}$

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