please solve this question and no wrong answer please
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Firstly BDC=75 (corresponding angles)
BDC + DBA = 180 ( sum of opposite angles is 180)
DBA = 105
So FBG = 105-10= 95
Also, GEF = 180-95= 85 (sum of opposite angles is 180 again)
Now by ASP in BGEF,
EGB= 360-(75+85+95) = 105
Do angles of BGEF are 105,75,85 and 95
BDC + DBA = 180 ( sum of opposite angles is 180)
DBA = 105
So FBG = 105-10= 95
Also, GEF = 180-95= 85 (sum of opposite angles is 180 again)
Now by ASP in BGEF,
EGB= 360-(75+85+95) = 105
Do angles of BGEF are 105,75,85 and 95
Answered by
0
Step-by-step explanation:
angle BGC = 180 - 95 ( linear pair)
= 85
taking CE as a transversal of parallel sides cd and ef
angle dce + angle cef = 180 [ interior angles of side of transversal ]
95 + angle cef =180
angle cef = 180 -95
= 85
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