Question

please solve this question and sent me​

Answer 1

Answer:

6m

Step-by-step explanation:

These two are the answers of this question .

You can use the simplest one from these 2 answers .

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Answer 2

Answer:

$\huge\underline\purple {Answer}$

Given:-

Length of shadow = BC = 2√3m

Length of shadow = BC = 2√3mAngle of elevation = ^ACB = 60°

To find:-

Height of pole = AB = ?

$\huge\overbrace {Solution}$

In ∆ABC,

$\tan(60) \: = \: \frac{ab}{bc}$

$\sqrt{3} = \frac{ab}{2 \sqrt{3} }$

$ab \: = \sqrt{3} \times 2 \sqrt{3}$

$ab \: = 2 \times 3$

$ab \: = 6$

$\huge\underbrace\pink {AB = 6m}$