Math, asked by muskan5018, 1 year ago

please solve this question anyone​

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Answers

Answered by aslampkhan9140
3

first take out factors of

under roots

it will be (4/3+5/2)/(4/3+3/2)

here i have taken/ inside brackets as under root

solve this u will get ans 1

Answered by Anonymous
3

 &lt;img </p><p>Src ="http://majatisel.com/hello.gif"width =" 300"height ="315" &gt;

 \huge \mathcal {\pink {Rationalizing}}

 &lt;b &gt;&lt;font color ="pink" &gt;

 =  &gt;  \frac{4 \sqrt{3}  + 5 \sqrt{2} }{ \sqrt{48}  +  \sqrt{18} } \\  \\  =  &gt;  \frac{4 \sqrt{3}  + 5 \sqrt{2} }{4 \sqrt{3} + 3 \sqrt{2}  }   \\  \\  =  &gt;  \frac{4 \sqrt{3}  + 5 \sqrt{2} }{4 \sqrt{3} + 3 \sqrt{2}  }   \times  \frac{4 \sqrt{3} + 3 \sqrt{2}  }{4 \sqrt{3}  + 3 \sqrt{2} }  \\  \\   =  &gt;  \frac{(4 \sqrt{3} + 5 \sqrt{2}  )(4 \sqrt{3}  + 3 \sqrt{2} }{ {(4 \sqrt{3)} }^{2}  +  {(3 \sqrt{2} )}^{2} }  \\  \\  =  &gt;  \frac{4 \sqrt{3} (4 \sqrt{3}  + 5 \sqrt{2}) + 3 \sqrt{2} (4 \sqrt{2}  + 5 \sqrt{2}  }{48 + 18}  \\  \\  =  &gt;  \frac{48 + 20 \sqrt{6}  + 12 \sqrt{6}  + 30}{66}  \\  \\  =  &gt;  \frac{78 + 32 \sqrt{6} }{66}  \\  \\  =  &gt;  \frac{78 +  8 \sqrt{3} }{66}  \\  \\  =  &gt;  \frac{78 }{66} +  \frac{8 \sqrt{3} }{66}   \\  \\  =  &gt;  \frac{39}{33}   +  \frac{4 \sqrt{3} }{33}  \\  \\  =  &gt;  \frac{39 + 4 \sqrt{3} }{33}

&lt;/b &gt;&lt;/font &gt;

 \huge \mathcal {\pink {Hope \:you \:got \:it}}

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