Question

please solve this question anyone​

Answer 1

Step-by-step explanation:

Given:-

Length of the rectangle is 7 units breadth is 3 units and height of the triangle is 3 units

To find:-

Area of the given figure?

Solution:-

Given figure consists of two figures they are rectangle and triangle

Total area of the figure = Area of a rectangle + Area of a triangle

Area of the rectangle:-

Length of the rectangle =7 units

Breadth of the rectangle =3 units

Area of the rectangle =lb units^2

=>7×3 units^2

=>21 units^2----(1)

Area of the triangle:-

Base of the traingle =7 units

Height of the triangle =3 units

Area of a triangle=1/2 bh units^2

=>7×3/2 units^2

=>21/2 units^2

=>10.5 units^2------(2)

On adding (1)&(2)

=>21+10.5

=>31.5 units^2

Answer:-

Total area of the given figure =31.5 units^2

Used formulae:-

• Area of the rectangle=lb units^2
• Area of the triangle=1/2 bh units^2

Answer 2

$\large\underline\purple{\bold{Solution :- }}$

The given figure consist of two plane objects. One is rectangle and other is triangle.

So, Area of figure = Area of rectangle + Area of triangle.

Dimensions of rectangle

Length = 7 units

Breadth = 3 units

Area of rectangle = Length × Breadth

$\red{ \bf \: Area_{(rectangle)}} \: = \tt \: 7 \times 3 \: = 21 \: {units}^{2}$

Dimensions of triangle

Base = 7 units

Height = 3 units

$\sf \: Area \: of \: triangle \: = \dfrac{1}{2} \times base \times height$

$\red{ \bf \: Area_{(triangle)}} \: = \tt \: \dfrac{1}{2} \times 7 \times 3 = 10.5 \: {units}^{2}$

So,

$\bf \: Area_{(figure)} \: = Area_{(rectangle)} + \: Area_{(triangle)}$

$\bf \: Area_{(figure)} \: =21 + 10.5 = 31.5 \: {units}^{2}$