please solve this question as early as possible
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The Haber prpcess chemical reaction is as follows
N2 + 3H2 = 2NH3
By Avagadro's Law we can say that the volumes are in the ratio 1:3:2
So if 10 litres of N2 and 30 litres of H2 are taken, 20 litres of NH3 is obtained.
So if full reaction happens with the given quantities,
30 L of H2 is used 0 Litres of is left.
10 L of N2 is used, 20 L is left
20 L of NH3 is formed.
But only half reaction occurs.
So only 10L of NH3 is formed. so according to the ration,
5 litres of N2 is used, 25L is left.
15 litres of H2 is used, 15 L is left.
So the resultant mixture consists of
10L NH3
25L N2
15L H2
N2 + 3H2 = 2NH3
By Avagadro's Law we can say that the volumes are in the ratio 1:3:2
So if 10 litres of N2 and 30 litres of H2 are taken, 20 litres of NH3 is obtained.
So if full reaction happens with the given quantities,
30 L of H2 is used 0 Litres of is left.
10 L of N2 is used, 20 L is left
20 L of NH3 is formed.
But only half reaction occurs.
So only 10L of NH3 is formed. so according to the ration,
5 litres of N2 is used, 25L is left.
15 litres of H2 is used, 15 L is left.
So the resultant mixture consists of
10L NH3
25L N2
15L H2
sona561:
thanks a lot
Answered by
4
By Avagadro's Law we can say that the volumes are in the ratio 1:3:2
So if 10 litres of N2 and 30 litres of H2 are taken, 20 litres of NH3 is obtained.
So if full reaction happens with the given quantities,
30 L of H2 is used 0 Litres of is left.
10 L of N2 is used, 20 L is left
20 L of NH3 is formed.
But only half reaction occurs.
So only 10L of NH3 is formed. so according to the ration,
5 litres of N2 is used, 25L is left.
15 litres of H2 is used, 15 L is left.
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