Question

please solve this question as fast as possible​

Answer 1

Answer:

14 years

Step-by-step explanation:

Let the present age of Zeba be 'x' years.

Given that She were younger by 5 years than what she really is.

Zeba's age when she was 5 years younger = (x - 5) years.

Given that the square of her age would have been 11 more than 5 times.

⇒ (x - 5)² = 5x + 11

⇒ x² + 25 - 10x = 5x + 11

⇒ x² - 15x + 14 = 0

⇒ x² - 14x - x + 14 = 0

⇒ x(x - 14) - (x - 14) = 0

⇒ (x - 14)(x - 1) = 0

⇒ x = 14,1{∵ Present age cannot be 1 year}

⇒ x = 14.

Therefore, Age of Zeba is 14 years.

Hope it helps!

Answer 2

$\underline{\underline{\bold{Question:}}}$

If Zeba were younger by 5 years than What she really is , then the square of her age (in years) would have been 11 more than 5 times her actual age . What is her age now ?

$\underline{\bold{Solution:}}$

$\tt{Let\:the\:Zeba's\:present\:age\:be\:x\:years.}$

5 years ago ,

• The age of Zeba was = (x-5) years.

According to question,

$\implies{\bold{(x-5)^2=5x+11}}\\\\\\\boxed{\bold{(a+b)^2=a^2+2ab+b^2}}\\\\\\\implies{\bold{x^2-2*x*5+5^2=5x+11}}\\\\\\\implies{\bold{x^2-10x-5x+25-11=0}}\\\\\\\implies{\bold{x^2-15x+14=0}}\\\\\\\implies{\bold{x^2-x-14x+14=0}}\\\\\\\implies{\bold{x(x-1)-14(x-1)=0}}\\\\\\\implies{\bold{(x-14)(x-1)=0}}\\\\\\\implies{\bold{x=\left \{ {{1} \atop {14}} \right. }}\\\\\\\boxed{\boxed{\bold{The\:present\:age\:of\:Zeba=14\:years.}}}$