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construction of DB such that it intersects EF at M.
now, since EF II AB and E is midpoint,
M is midpoint of DB (i)
EM= AB/2 (from midpoint theorem) (ii)
similarly, since EF II AB and M is midpoint,
F is midpoint of CB
FM = CD/2 (from midpoint theorem) (iii)
Adding (ii) and (iii),
EM+ FM = 1/2(AB +CD)
EF = 1/2(A+B)
now, since EF II AB and E is midpoint,
M is midpoint of DB (i)
EM= AB/2 (from midpoint theorem) (ii)
similarly, since EF II AB and M is midpoint,
F is midpoint of CB
FM = CD/2 (from midpoint theorem) (iii)
Adding (ii) and (iii),
EM+ FM = 1/2(AB +CD)
EF = 1/2(A+B)
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