Question

Please solve this question ASAP ​

Answer 1

Answer:

Given:

sin Ф = 3/4

⇒ P = 3 AND H = 4

USING PYTHAGORAS THEOREM; WE WILL GET:-

B = √7

So, cosec Ф = 1/sinФ = 4/3

Now:-

√(cosec²Ф-cot²Ф/sec²Ф-1)

√((4/3)²- (B/P)²/tan²Ф)        {∵ sec²Ф -1 = tan²Ф}

√(16/9 - (√7/3)²/(P/B)²)

√(16/9 - (7/9) / (3/√7)²)

√((16-7/9)/9/7)

√(9/9) X 7/9

√1 X 7/9

√7/3

Step-by-step explanation:

Hope it helps you buddy :)