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Answer:
Given:
sin Ф = 3/4
⇒ P = 3 AND H = 4
USING PYTHAGORAS THEOREM; WE WILL GET:-
B = √7
So, cosec Ф = 1/sinФ = 4/3
Now:-
√(cosec²Ф-cot²Ф/sec²Ф-1)
√((4/3)²- (B/P)²/tan²Ф) {∵ sec²Ф -1 = tan²Ф}
√(16/9 - (√7/3)²/(P/B)²)
√(16/9 - (7/9) / (3/√7)²)
√((16-7/9)/9/7)
√(9/9) X 7/9
√1 X 7/9
√7/3
Step-by-step explanation:
Hope it helps you buddy :)
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