Question

Please solve this question asap.

The best one would be marked as brainliest. ​

Answer 1

so it is your answer of your question

Step-by-step explanation:

hope it will help u

Answer 2

$\large\mathcal \red \bigstar{\underline{\purple{GIVEN:-}}}$

Principal=₹18000

Time=1.6 years or 18 months

rate=10% per annum or 0.1

____________________________

$\large\mathcal \red \bigstar{\underline{\blue{To\:Find:-}}}$

Amount and Compound Interest.

____________________________

$\large\mathcal \red\bigstar{\underline{\green{Formula}}}$➠

Amount:- P (1 + r/n)^(nt)

Compound Interest=A -P

where,

A = the future value of the investment/loan, including interest.

P = the principal investment amount.

r = the annual interest rate (decimal).

n = the number of times that interest is compounded per unit t.

t = the time the money is invested or borrowed for

If interest is ➠

compounded yearly, then n = 1 semi-annually, then n = 2

quarterly, then n = 4

monthly, then n = 12

weekly, then n = 52

____________________________

$\large\mathcal \red \bigstar{\underline{\pink{SOLUTION:-}}}$

Amount = P (1 + r/n)^(nt)

=18000(1+0.1/1)^(1×3/2)

=18000(1.1)^(3/2)

=18000×1.15

=20,766$\red\bigstar{Answer}\red\bigstar$

Compound Interest=A-P

=>. 20,766-18000

=> ₹2766. $\red\bigstar{Answer}\red\bigstar$