Math, asked by yuvti, 9 months ago

please solve this question
brilliant can solve this answer​

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Answered by ekanshpandey2004
0

Answer:

Step-by-step explanation:

AC is parallel to EB and EA is parallel to BC

Hence, ACBE is parallelogram.

and ,

AF is parallel to BC and AB is parallel to CF.

Hence, ABCF is parallelogram.

and , parallelogram ACBE and parallelogram ABCF is on same base BC and between same parallel lines EF and BC.

ar(ACBE)= ar(ABCF)

AND,

1/2×ar(ACBE)= 1/2×ar(ABCF)

ar(ABE) = ar(ACF)

hence, proved.

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