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Step-by-step explanation:
AC is parallel to EB and EA is parallel to BC
Hence, ACBE is parallelogram.
and ,
AF is parallel to BC and AB is parallel to CF.
Hence, ABCF is parallelogram.
and , parallelogram ACBE and parallelogram ABCF is on same base BC and between same parallel lines EF and BC.
ar(ACBE)= ar(ABCF)
AND,
1/2×ar(ACBE)= 1/2×ar(ABCF)
ar(ABE) = ar(ACF)
hence, proved.
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