Question

Please solve this question by graph.​

Answer 1

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Answer 2

$\large\underline{\sf{Solution-}}$

Given that,

↝ 35% students in a class are girlś and rest are boys.

Let assume that

↝ Number of girlš = x

↝ Number of boys = y

Thus,

$\rm :\longmapsto\:x = 35\% \: of \: (x + y)$

$\rm :\longmapsto\:x = \dfrac{35}{100}(x + y)$

$\rm :\longmapsto\:x = \dfrac{7}{20}(x + y)$

$\rm :\longmapsto\:20x = 7x + 7y$

$\rm :\longmapsto\:20x - 7x = 7y$

$\rm :\longmapsto\:13x = 7y$

$\rm \implies\:\boxed{ \tt{ \: \: y = \frac{13}{7} \: x \: \: }}$

Substituting 'x = 0' in the given equation, we get

$\rm :\longmapsto\:y = \dfrac{13}{7} \times 0$

$\rm :\longmapsto\:y =0$

Substituting 'x = 7' in the given equation, we get

$\rm :\longmapsto\:y = \dfrac{13}{7} \times 7$

$\rm :\longmapsto\:y = 13$

Substituting 'x = 14' in the given equation, we get

$\rm :\longmapsto\:y = \dfrac{13}{7} \times 14$

$\rm :\longmapsto\:y =13 \times 2$

$\rm :\longmapsto\:y =26$

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf 0 \\ \\ \sf 7 & \sf 13 \\ \\ \sf 14 & \sf 26 \end{array}} \\ \end{gathered}$

➢ Now draw a graph using the points

➢ See the attachment graph.

From graph we concluded that

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 21 & \sf 39 \\ \\ \sf 14 & \sf 26 \end{array}} \\ \end{gathered}$