Question

please solve this question by Quadric formula​

-3x² + 5x + 12 = 0

Answer 1

Answer:

$\large x=\dfrac{-4}{3} \ or \ x=3$

Step-by-step explanation:

Given :

$\large p(x)=-3x^2+5x+12=0$

We have Quadratic formula​

$\large \text{ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a} }$

Comparing values from given

a = - 3 , b = 5  and c = 12

Now put values in formula we get

$\large \text{ x=\dfrac{-5\pm\sqrt{5^2-4\times-3\times12}}{2\times-3} }\\\\\\\large \text{ x=\dfrac{-5\pm\sqrt{25+144}}{-6} }\\\\\\\large \text{ x=\dfrac{-5\pm\sqrt{169}}{-6} }\\\\\\\large x=\dfrac{-5\pm13}{-6} \\\\\\\large x=\dfrac{-5+13}{-6} \ or \ x=\dfrac{-5-13}{-6}\\\\\\\large x=\dfrac{8}{-6} \ or \ x=\dfrac{-18}{-6}\\\\\\\large x=\dfrac{-4}{3} \ or \ x=3$

Thus we get answer.